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/ = 7 \times 13
= 7 \times 13
February 22, 2026
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\( n > \sqrt{1000} \).
\( 10 \times 3.162 = 31.62 \).
= 2 \times 3 \times 13
= \frac{1000}{1 + 9e^{-0.5t}}
+ 9e^{-0.5t} = 2
-0.5t = \ln\left(\frac{1}{9}\right) = -\ln 9
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