+ 2m = 8
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- Solution: Given $ v(t) = t^2 - 4t + mt $ and $ v(2) = 8 $, substitute $ t = 2 $:
- v(2) = (2)^2 - 4(2) + m(2) = 4 - 8 + 2m = -4 + 2m
- Set equal to 8:
- 2m = 12
- m = 6
- Hence, the truth-weight parameter is $ oxed{6} $.Question: Find $ x $ such that the vectors $ egin{pmatrix} x \ 2 \end{pmatrix} $ and $ egin{pmatrix} 3 \ -x \end{pmatrix} $ are orthogonal.
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