A satellite orbits Earth in a circular path with a radius of 6,700 km. If it completes one orbit every 90 minutes, what is its average speed in kilometers per hour?
["What Drives Interest in Satellite Orbits Like the One Circling Earth Every 90 Minutes? \nA satellite orbits Earth in a near-circelar path with a radius of 6,700 km, completing one full revolution every 90 minutes. This precise motion fuels real-world curiosity among tech enthusiasts, students, and future space contributors. As global interest in space continues to grow—sparked by commercial launches, satellite internet, and Earth observation—understanding the math behind orbital mechanics becomes both accessible and relevant. Recent cultural momentum around space exploration has amplified public awareness, making precise orbital calculations a topic tens of thousands search for, especially in the U.S., where innovation and STEM engagement are core priorities.", "Why This Satellite Orbit Matters Today \nThe Earth’s 6,700 km orbital radius and 90-minute cycle represent fundamental aspects of low-Earth orbit (LEO) dynamics, closely tied to active use cases like satellite communication, climate monitoring, and international space collaboration. As private companies expand constellations for global internet coverage and governments invest in Earth imaging, the practical importance of orbital speed appears more visible than ever. Public fascination increases when technical facts align with tangible benefits—making calculations about speed not just academic, but insightful for anyone tracking technological progress. The orbiting satellite’s average velocity, often sought in online searches, highlights how orbital physics underpins modern connectivity and environmental awareness.", "How to Calculate Orbital Speed: A Clear Explanation \nTo find a satellite’s average speed, we use the formula for circular motion: speed equals circumference divided by time. First, the circular path’s circumference is calculated using the formula $ C = 2\pi r $. With a radius of 6,700 km, the circumference is $ C = 2 \ imes \pi \ imes 6,700 \approx 42,097 \ ext{ km} $. Since it completes one orbit in 90 minutes, this equals $ 1.5 $ hours. Dividing circumference by time gives average speed: \n$ \ ext{Speed} = 42,097 \ ext{ km} \div 1.5 \ ext{ hours} \approx 28,065 \ ext{ km/h} $."]
